5t^2+4t+1=0

Solution for 5t^2+4t+1=0 equation:

Simplifying
5t2 + 4t + 1 = 0

Reorder the terms:
1 + 4t + 5t2 = 0

Solving
1 + 4t + 5t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + 0.8t + t2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + 0.8t + -0.2 + t2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + 0.8t + t2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + 0.8t + t2 = 0 + -0.2
0.8t + t2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
0.8t + t2 = -0.2

The t term is 0.8t.  Take half its coefficient (0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
0.8t + 0.16 + t2 = -0.2 + 0.16

Reorder the terms:
0.16 + 0.8t + t2 = -0.2 + 0.16

Combine like terms: -0.2 + 0.16 = -0.04
0.16 + 0.8t + t2 = -0.04

Factor a perfect square on the left side:
(t + 0.4)(t + 0.4) = -0.04

Can't calculate square root of the right side.

The solution to this equation could not be determined.